document.write( "Question 1135312: Finding the number of cycles in 2 pi, the horizontal length of each of the 4 quadrants of each cycle =, vertical shift, horizontal shift of each cycle, and determining a reflection over the x axis. \r
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document.write( "f(theta)=4sin(3theta+theta/4)-10 \n" );
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Algebra.Com's Answer #752979 by Theo(13342) You can put this solution on YOUR website! this graph is a little different.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i use x for theta and y for f(x), so the formula in my language is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 4 * sin(3x + x/4) - 10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it's the same formula except it's easier to graph this way using the graphing calculator at desmos.com.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "within the parentheses, 3x + x/4 is equivalent to 12x/4 + x/4; which is equal to 13x/4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that translates to the frequency being 13/4 * x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "there is no horizontal shift.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it's just a frequency change.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the frequency is 13/4, then the period of the sine function is equal to 2 * pi / (13/4) which is equal to 2 * pi * 4 / 13 which is equal to 8/13 * pi.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your sine function of y = 4 * sin(3x + x/4) - 10 translates to y = 4 * sin(13/4 * x) - 10.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the amplitude is 4. \n" ); document.write( "the vertical displacement is -10. \n" ); document.write( "the frequency is 13/4 \n" ); document.write( "the period is 8/13 * pi.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's the graph from 0 radians to 8pi/13 radians.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "\n" ); document.write( "here's the graph from 8pi/13 radians to 16pi/13 radians.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the amplitude is 4. \n" ); document.write( "the center line is at y = -10 \n" ); document.write( "that means the high point of the graph is y = -10 + 4 which becomes y = -6. \n" ); document.write( "that means the low point of the graph is y = -10 - 4 which becomes y = -14. \n" ); document.write( "the period is 8pi/13 radians. \n" ); document.write( "that means one cycle goes from 0 to 8pi/13 and from 8pi/13 to 16pi/13.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |