document.write( "Question 1135343: What is the solution to this problem?\r
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Algebra.Com's Answer #752934 by rothauserc(4718) $\"\"$ $\"About$

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32^(2y) = 5^(4y+1)
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\n" ); document.write( "(32^2)^y = (5^(4)^y) * 5
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\n" ); document.write( "1024^y = 625^y * 5
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\n" ); document.write( "take ln (natural log) of both sides of =
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\n" ); document.write( "yln(1024) = yln(625) +ln(5)
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\n" ); document.write( "Note ln(a^b) = bln(a) and ln(ab) = ln(a) + ln(b)
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\n" ); document.write( "yln(1024) - yln(625) = ln(5)
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\n" ); document.write( "y(ln(1024) - ln(625)) = ln(5)
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\n" ); document.write( "yln(1024/625) = ln(5)
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\n" ); document.write( "Note ln(a) - ln(b) = ln(a/b)
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\n" ); document.write( "y = ln(5)/ln(1024/625)
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\n" ); document.write( "y = 3.2598
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