document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1135289>Question 1135289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (4 pts) For f (x) = x3  -  3x2  -  6, use the Intermediate Value Theorem to determine which interval must contain a zero of f. (no explanation required)<BR>\n" );
document.write( "A. Between 0 and 1<BR>\n" );
document.write( "B. Between 1 and 2<BR>\n" );
document.write( "C. Between 2 and 3<BR>\n" );
document.write( "D. Between 3 and 4<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #752933 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=752933\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The function is a polynomial, so its graph is continuous and differentiable everywhere.<br><BR>\n" );
document.write( "f(0) = -6<BR>\n" );
document.write( "f(1) = -8<BR>\n" );
document.write( "f(2) = -10<BR>\n" );
document.write( "f(3) = -6<BR>\n" );
document.write( "f(4) = 10<br><BR>\n" );
document.write( "f(3) is negative; f(4) is positive  -->  there must be a zero between 3 and 4.  Answer D </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );