document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1135334>Question 1135334</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jerry spent 2.5 hours biking up Mount Lowe, rested at the top for 30 minutes, and biked down in 1.5 hours. How far did he bike if his rate of ascent was 3 km/h less than his rate of descent? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #752920 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=752920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Speed going up is x km/h or 2.5x km distance<BR>\n" );
document.write( "speed going down is (x+3) km/h or 1.5(x+3) or 1.5x+4.5 km<BR>\n" );
document.write( "Those distances are equal<BR>\n" );
document.write( "so 2.5x=1.5x+4.5<BR>\n" );
document.write( "or x=4.5 km/h<BR>\n" );
document.write( "It was 11.25 km up (2.5 x)<BR>\n" );
document.write( "and 11.25 km down (1.5*7.5)\r<BR>\n" );
document.write( "\n" );
document.write( "He biked the sum or 22.5 km. </SPAN>\n" );
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