document.write( "Question 1135264: Please help me solve this equations
\n" ); document.write( "The circus is coming. Cindy is selling tickets. she sold 8 adults tickets and 5 children's tickets for a total of $180.50 in sales. The second day she received $261.00 for 12 adult tickets and 6 children tickets. What is the price of a child's ticket? What is the price of an adult ticket?
\n" ); document.write( "Write two algebraic equations that model this circus ticket scenario.
\n" ); document.write( "Show how you solved the problem by using elimination method, the substitution method, or the graphical method
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Algebra.Com's Answer #752897 by greenestamps(13198)\"\" \"About 
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\n" ); document.write( "If the two equations are both in the form Ax+By=C, then elimination is nearly always easier than substitution.

\n" ); document.write( "\"8A%2B5C+=+180.5\"
\n" ); document.write( "\"12A%2B6C+=+261\"

\n" ); document.write( "Multiply the first equation by 3 and the second by 2. That will make the coefficients of A both 24; then subtracting one equation from the other will eliminate A and let you solve for C.

\n" ); document.write( "\"24A%2B15C+=+541.5\"
\n" ); document.write( "\"24A%2B12C+=+522\"
\n" ); document.write( "\"3C+=+19.5\"
\n" ); document.write( "\"C+=+6.5\"

\n" ); document.write( "Substitute the value you found for C back in one of the original equations to solve for A.

\n" ); document.write( "\"8A%2B32.5+=+180.5\"
\n" ); document.write( "\"8A+=+148\"
\n" ); document.write( "\"A+=+18.5\"

\n" ); document.write( "The tickets cost $6.50 for a child and $18.50 for an adult.
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