document.write( "Question 103361: A bicyclist rode into the country for 5 h. In returning, her speed was 5 mi/h faster and the trip took 4 h. What was her speed eacy way? \n" ); document.write( "
Algebra.Com's Answer #75284 by ankor@dixie-net.com(22740)\"\" \"About 
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A bicyclist rode into the country for 5 h. In returning, her speed was 5 mi/h faster and the trip took 4 h. What was her speed each way?
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\n" ); document.write( "Let s = speed into the country
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\n" ); document.write( "(s+5) = speed returning
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\n" ); document.write( "The distance for both trips is the same. Write a distance equation
\n" ); document.write( "Dist = time * speed
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\n" ); document.write( "Dist into the country = Dist back from the country
\n" ); document.write( "5s = 4(s+5)
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\n" ); document.write( "5s = 4s + 20
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\n" ); document.write( "5s - 4s = 20
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\n" ); document.write( "s = 20 mph is into the country
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\n" ); document.write( "20 + 5 = 25 mph back.
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\n" ); document.write( "Check solution by finding if both trips are equal:
\n" ); document.write( "5*20 = 100
\n" ); document.write( "4*25 = 100
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\n" ); document.write( "Make sense to you now?
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