document.write( "Question 15137: The second of three numbers is 8 more that the first and the third number is 3 less than 3 times the first. If the tird number is 15 more than the second, find the three numbers.\r
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document.write( "Here's what I have for the variables:
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document.write( "First number = x
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document.write( "Second number = x + 8
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document.write( "third number = 3x - 3 and it is x + 8 + 15\r
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document.write( "Where do I go from here?? \n" );
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Algebra.Com's Answer #7528 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! The second of three numbers is 8 more that the first and the third number is 3 less than 3 times the first. If the tird number is 15 more than the second, find the three numbers.\r \n" ); document.write( "\n" ); document.write( "Here's what I have for the variables: \n" ); document.write( "First number = x \n" ); document.write( "Second number = x + 8 \n" ); document.write( "third number = 3x - 3 and it is x + 8 + 15\r \n" ); document.write( "\n" ); document.write( "Where do I go from here?? \n" ); document.write( " OH!! DEAR!! DEAR!! YOU GOT IT !! YOU ARE ALMOST AT THE FINISH LINE !!! JUMP AHEAD ! YOU WILL GET THE ANSWER!!! \n" ); document.write( " You rightly concluded that the third number is 3x-3 and it is x+8+15...MEANS WHAT ???? THEY ARE EQUAL ...SO \n" ); document.write( " 3x-3=x+8+15 \n" ); document.write( " 3x-x=8+15+3 \n" ); document.write( " 2x=26...or x=13..... hence the 3 numbers are as per your own working \n" ); document.write( " First number = x =13 \n" ); document.write( "Second number = x + 8=13+8 =21 \n" ); document.write( "third number = 3x - 3=3*13-3=36..check this if you want with \n" ); document.write( " x + 8 + 15 = 13+8+15 =36\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |