document.write( "Question 1135210: f(x)=6-3x^2,if x<0
\n" ); document.write( "find the inverse of the one to one function
\n" ); document.write( "f^-1(x)? \n" ); document.write( "

Algebra.Com's Answer #752794 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( " $\"f%28x%29=6-3x%5E2\"$ ,if $\"x%3C0\"$ \r
\n" ); document.write( "\n" ); document.write( "find the inverse of the one to one function\r
\n" ); document.write( "\n" ); document.write( " $\"f%5E-1%28x%29\"$ \r
\n" ); document.write( "\n" ); document.write( "since $\"f+%28x%29=y\"$ , we have\r
\n" ); document.write( "\n" ); document.write( " $\"y=6-3x%5E2\"$ .......swap $\"x\"$ and $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=6-3y%5E2\"$ ........solve for $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3y%5E2=6-x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y%5E2=%286-x%29%2F3\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y=sqrt%28%286-x%29%2F3%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%5E-1%28x%29=sqrt%28%286-x%29%2F3%29\"$ \r
\n" ); document.write( "\n" ); document.write( "so your inverse is: $\"y=sqrt%28%286-x%29%2F3%29\"$ or $\"y=-sqrt%28%286-x%29%2F3%29\"$ \r
\n" ); document.write( "\n" ); document.write( "and it is one to one function\r
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