document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=103554>Question 103554</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0866099654/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> the measure of the supplement of an angle is 30 degrees less than 5 times the measure of the compliment find 2/5 the measure of the compliment </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75277 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the measure of the supplement of an angle is 30 degrees less than 5 times the measure of the compliment find 2/5 the measure of the compliment<BR>\n" );
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document.write( "Let the angle be \"x\"; supplement is \"180-x\"; complement is \"90-x\"<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "180-x = 5(90-x)-30<BR>\n" );
document.write( "180-x = 450-5x-30<BR>\n" );
document.write( "4x = 240<BR>\n" );
document.write( "x = 60 degrees<BR>\n" );
document.write( "complement = 90-x = 30 degrees<BR>\n" );
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document.write( "(2/5)30 = 12 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );