document.write( "Question 1135161: Hello I am graphing the vertex and axis of symmetry and I understand how to find it, but how about when the vertex is a fraction? How would I graph the vertex? (if x and y are in fraction form) \n" ); document.write( "
Algebra.Com's Answer #752718 by MathLover1(20849)\"\" \"About 
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The axis of symmetry always passes through the vertex of the parabola . The -coordinate of the vertex is the equation of the axis of symmetry of the parabola. For a quadratic function in standard form, \"y+=+a+x%5E2+%2B+b+x+%2B+c\" , and in vertex form \"y=a%28x-h%29%5E2%2Bk\" the axis of symmetry is a vertical line \"x+=+-b%2F+2a\"\r
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\n" ); document.write( "\n" ); document.write( " \"y=x%5E2-x%2B1\"....use vertex form to find coordinates\r
\n" ); document.write( "\n" ); document.write( "\"y=%28x%5E2-x%2Bb%5E2%29-b%5E2%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%28x%5E2-x%2B%281%2F2%29%5E2%29-%281%2F2%29%5E2%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%28x-1%2F2%29%5E2-1%2F4%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%28x-1%2F2%29%5E2-1%2F4%2B4%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%28x-1%2F2%29%5E2%2B3%2F4\"\r
\n" ); document.write( "\n" ); document.write( "so, \"h=1%2F2\" and \"k=3%2F4\" and vertex is at (\"1%2F2\", \"3%2F4\")\r
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