document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=14481>Question 14481</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i need help solving these 2 linear  equation problems. they both must be solved using elimination only.<BR>\n" );
document.write( " 1.  x - 6y = 3                  2.  6x + -4y = 12<BR>\n" );
document.write( "    3x+ 2y = 1                       9x  - 6y = 18\r<BR>\n" );
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document.write( "These 2 problems must b only solved using  elimination.  please i need help i tried i feel like its wrong </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7527 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     x - 6y = 3....(1) ; 3x+ 2y = 1.....(2)  Let me explain elimination to you.there are  2 unknowns. we can easily solve if there is only 1 unknown.so we try to eliminate 1 unknown. say x .<BR>\n" );
document.write( "see coefficient of x in both eqns.,1 and 3. find their lcm .it is 3. so multiply eqn.1 with 3 to get 3x and eqn.2 with 1 to get the same 3x.having made coefficient of x same in the 2 eqns.,add or subtract them to eliminate x.<BR>\n" );
document.write( " eqn.(1)*3....3x-18y=9......(3)<BR>\n" );
document.write( " eqn.(2)*1....3x+2y=1........(4)<BR>\n" );
document.write( " eqn(3)-eqn.(4)......-18y-2y=9-1...or -20y=8..or  y=-8/20=-2/5.<BR>\n" );
document.write( "  now substitute this value of y in any eqn.say eqn.(1) to get x value<BR>\n" );
document.write( "   x-6*(-2/5)=3...<BR>\n" );
document.write( "   x=3-12/5=(15-12)/5 = 3/5.<BR>\n" );
document.write( "  to check your answer substitute these 2 values of x and y in the given equations and check for compliance.<BR>\n" );
document.write( " Eqn.(1)....3/5 -6*(-2/5)= 3/5 +12/5 =15/5 = 3 =rhs ...ok.<BR>\n" );
document.write( " Eqn.(2)....3*(3/5)+2*(-2/5)=9/5-4/5=5/5=1 = rhs ...ok<BR>\n" );
document.write( "  now i leave the second problem for you to do  as practice          <BR>\n" );
document.write( "                         <BR>\n" );
document.write( "    6x + -4y = 12<BR>\n" );
document.write( "    9x  - 6y = 18<BR>\n" );
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