document.write( "Question 1135104: Show that \"f%28x%29=x%5E2%2B6x%2B12\" is always positive for all values of x \n" ); document.write( "
Algebra.Com's Answer #752654 by ikleyn(52786)\"\" \"About 
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document.write( "\"x%5E2+%2B+6x+%2B+12\" = \"%28x%5E2+%2B+6x+%2B+9%29\" + 3 = \"%28x%2B3%29%5E2\" + 3.\r\n" );
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document.write( "So, this expression is the sum of two terms.\r\n" );
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document.write( "First term is quadratic binomial  \"%28x%2B3%29%5E2\",  which ALWAYS is non-negative as a square of a real number.\r\n" );
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document.write( "The second term is constant term \"3\", which is positive, too.\r\n" );
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document.write( "Therefore, their sum is ALWAYS positive.\r\n" );
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document.write( "Thus, the original expression is always positive, too.\r\n" );
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\n" ); document.write( "\n" ); document.write( "It is a TEMPLATE and a SAMPLE to you on how this and similar problems should be solved and worded.\r
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\n" ); document.write( "\n" ); document.write( "The method which I used  is called \"completing the square\".\r
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\n" ); document.write( "\n" ); document.write( "On how this method works,  you can read from the lesson\r
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