document.write( "Question 1135050: Betty ann drove from city A TO B a distance of 250 miles she increased her speed by 10 mi/hr for the 360 mile trip from B TO C.\r
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\n" ); document.write( "\n" ); document.write( "if the total trip took 11 hours what was her speed from city A to city B.
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Algebra.Com's Answer #752611 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Betty ann drove from city A TO B a distance of 250 miles she increased her speed by 10 mi/hr for the 360 mile trip from B TO C.\r
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\n" ); document.write( "\n" ); document.write( "if the total trip took 11 hours what was her speed from city A to city B.
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Let speed from A to B. be S
\n" ); document.write( "Then speed from B to C is, S + 10
\n" ); document.write( "We then get the following TIME equation: \"matrix%281%2C3%2C+250%2FS+%2B+360%2F%28S+%2B+10%29%2C+%22=%22%2C+11%29\"
\n" ); document.write( "250(S + 10) + 360S = 11S(S + 10) ------- Multiplying by LCD, S(S + 10)
\n" ); document.write( "\"matrix%281%2C3%2C+250S+%2B+%222%2C500%22+%2B+360S%2C+%22=%22%2C+11S%5E2+%2B+110S%29\"
\n" ); document.write( "\"matrix%281%2C3%2C+610S+%2B+%222%2C500%22%2C+%22=%22%2C+11S%5E2+%2B+110S%29\"
\n" ); document.write( "\"matrix%281%2C3%2C+11S%5E2+%2B+110S+-+610S+-+%222%2C500%22%2C+%22=%22%2C+0%29\"
\n" ); document.write( "\"matrix%281%2C3%2C+11S%5E2+-+500S+-+%222%2C500%22%2C+%22=%22%2C+0%29\"
\n" ); document.write( "\"matrix%281%2C3%2C+11S%5E2+-+550S+%2B+50S+-+%222%2C500%22%2C+%22=%22%2C+0%29\"
\n" ); document.write( "11S(S - 50) + 50(S - 50) = 0
\n" ); document.write( "(S - 50)((11S + 50) = 0
\n" ); document.write( "Speed from A to B, or \"highlight_green%28matrix%281%2C4%2C+S%2C+%22=%22%2C+50%2C+mph%29%29\" OR \"matrix%281%2C4%2C+S%2C+%22=%22%2C+-+50%2F11%2C+%22%28ignore%29%22%29\" \n" ); document.write( "
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