document.write( "Question 1135052: lauren purchased a box of burgers for 35$ at her usual grocery store. When she got back home she saw a flyer for a different store advertising a price that was 50 cents less per burger. if laura has shopped at the second store she could have bought 8 more burgers for the same price\r
\n" ); document.write( "\n" ); document.write( "what was the price of one of the burgers lauren bought?
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Algebra.Com's Answer #752580 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "There are many ways to solve this kind of problem. The following is likely not the easiest -- just what seems to me the \"obvious\" way to get started.

\n" ); document.write( "Let n be the number of burgers and p be the price of each. Then

\n" ); document.write( "\"np+=+35\" the cost of the burgers she bought was $35
\n" ); document.write( "\"%28n%2B8%29%28p-1%2F2%29+=+35\" the cost of 8 more burgers at a price 50 cents less each would also have been $35

\n" ); document.write( "\"np+=+%28n%2B8%29%28p-1%2F2%29\"
\n" ); document.write( "\"np+=+np-%281%2F2%29n%2B8p-4\"
\n" ); document.write( "\"8p+=+%281%2F2%29n%2B4\"
\n" ); document.write( "\"16p+=+n%2B8\"
\n" ); document.write( "\"n+=+16p-8\"

\n" ); document.write( "Substitute that back into the first equation:

\n" ); document.write( "\"p%2816p-8%29+=+35\"
\n" ); document.write( "\"16p%5E2-8p+=+35\"
\n" ); document.write( "\"16p%5E2-8p-35+=+0\"
\n" ); document.write( "\"%284p-7%29%284p%2B5%29+=+0\"
\n" ); document.write( "\"p+=+7%2F4+=+1.75\" or \"p+=+-5%2F4+=+-1.25\"

\n" ); document.write( "A negative price doesn't make any sense, so the price per burger she paid was $1.75.

\n" ); document.write( "CHECK: $35 at $1.75 each --> 20 burgers;
\n" ); document.write( "28 burgers at $1.25 each = $35
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