document.write( "Question 1135050: Betty ann drove from city A TO B a distance of 250 miles she increased her speed by 10 mi/hr for the 360 mile trip from B TO C.\r
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document.write( "if the total trip took 11 hours what was her speed from city A to city B. \n" );
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Algebra.Com's Answer #752572 by swincher4391(1107)![]() ![]() You can put this solution on YOUR website! 250 = r*t\r \n" ); document.write( "\n" ); document.write( "360 = (r+10)*(11-t)\r \n" ); document.write( "\n" ); document.write( "360 = 11r -rt + 110 - 10t\r \n" ); document.write( "\n" ); document.write( "360 = 11r - 250 + 110 - 10t\r \n" ); document.write( "\n" ); document.write( "360 = 11r -140 - 10t\r \n" ); document.write( "\n" ); document.write( "We want to find r. Solve t in terms of r.\r \n" ); document.write( "\n" ); document.write( "250/r = t\r \n" ); document.write( "\n" ); document.write( "360 = 11r - 140 - 10(250/r)\r \n" ); document.write( "\n" ); document.write( "360 = 11r - 140 - 2500/r\r \n" ); document.write( "\n" ); document.write( "360 = (11r^2 - 140r - 2500)/r\r \n" ); document.write( "\n" ); document.write( "360r = 11r^2 - 140r - 2500\r \n" ); document.write( "\n" ); document.write( "11r^2 - 500r - 2500 = 0\r \n" ); document.write( "\n" ); document.write( "(500 +- sqrt((-500)^2 - 4(11)(-2500))) / 22\r \n" ); document.write( "\n" ); document.write( "(500 +- sqrt(360000))/22\r \n" ); document.write( "\n" ); document.write( "(500 + 600) / 22 = 1100 / 22 = 50\r \n" ); document.write( "\n" ); document.write( "Hence, 50 mph.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |