document.write( "Question 1135025: What is the combined probability of the following events occurring: rolling 1 or
\n" ); document.write( "6 on a fair die, flipping 2 heads in a row on a fair coin, then rolling 2,3,4 or
\n" ); document.write( "5 on the same die. \n" ); document.write( "
Algebra.Com's Answer #752532 by Edwin McCravy(20060)\"\" \"About 
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What is the combined probability of the following events occurring: rolling 1 or
\n" ); document.write( "6 on a fair die, flipping 2 heads in a row on a fair coin, then rolling 2,3,4 or
\n" ); document.write( "5 on the same die.
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document.write( "That's four events in succession:\r\n" );
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document.write( "A.  2 ways out of 6 that the die can fall successfully, a probability of 2/6 which\r\n" );
document.write( "    reduces to 1/3.\r\n" );
document.write( "B.  1 way out of 2 ways the fair coin can fall successfully the first time, a\r\n" );
document.write( "    probability of 1/2.\r\n" );
document.write( "C.  1 way out of 2 ways the fair coin can fall successfully the second time, also\r\n" );
document.write( "    a probability of 1/2. \r\n" );
document.write( "D.  4 ways out of 6 that the die can fall successfully, a probability of 4/6 which\r\n" );
document.write( "    reduces to 2/3.\r\n" );
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document.write( "For those 4 events to occur in succession, the probability is the product of the\r\n" );
document.write( "probabilities, since they are independent events.\r\n" );
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document.write( "Answer: (1/3)(1/2)(1/2)(2/3) = 2/36 which reduces to 1/18.\r\n" );
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document.write( "Edwin
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