document.write( "Question 1134959: A small regional carrier accepted 16 reservations for a particular flight with 12 seats. 8 reservations went to regular customers who will arrive for the flight. Each of the remaining passengers will arrive for the flight with a 48% chance, independently of each other. \r
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document.write( "A) Find the probability that overbooking occurs.
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document.write( "B) Find the probability that the flight has empty seats. \n" );
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Algebra.Com's Answer #752478 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! empty seats mean that no more than 3 of the other 8 will arrive for the flight. \n" ); document.write( "probability of 3 arriving is 8C3*0.48^3*0.52^5=0.2355 \n" ); document.write( "probability of 2 arriving is then 0.1275 \n" ); document.write( "probability of 1 is 0.0395 \n" ); document.write( "probability of 0 is 0.0053 \n" ); document.write( "That sum is 0.4078 ANSWER B \n" ); document.write( "overbooking is 5,6,7,8. \n" ); document.write( "do just 4, even though this isn't asked for \n" ); document.write( "probability is 70*0.48^4*0.52^4=0.2717 \n" ); document.write( "This plus the 0.4078 is 0.6795\r \n" ); document.write( "\n" ); document.write( "That is the probability no overbooking will occur. The probability that overbooking will occur is the complement of 0.3205 ANWER A \n" ); document.write( " |