document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=103474>Question 103474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation h=-16tē  + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180 ft.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75244 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75244\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 180=-16t^2+112t<BR>\n" );
document.write( "16t^2-112t+180=0<BR>\n" );
document.write( "(4t-18)(4t-10)=0<BR>\n" );
document.write( "4t-18=0<BR>\n" );
document.write( "4t=18<BR>\n" );
document.write( "t=18/4<BR>\n" );
document.write( "t=4.5 answer.<BR>\n" );
document.write( "4t-10=0<BR>\n" );
document.write( "4t=10<BR>\n" );
document.write( "t=10/4<BR>\n" );
document.write( "t=2.5 answer. </SPAN>\n" );
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