document.write( "Question 1134928: According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. [Round your answers to three decimal places, for example: 0.123]\r
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Algebra.Com's Answer #752427 by ikleyn(52788)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "(a)  Compute the probability that two randomly selected peanut M&M’s are both brown.\r\n" );
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document.write( "         P = 0.12*0.12 = 0.0144 = 0.014 (rounded as requested).    ANSWER\r\n" );
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document.write( "             ( 0.12 = 12% )\r\n" );
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document.write( "(b)  If you randomly select two peanut M&M’s, compute that probability that neither of them are orange.\r\n" );
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document.write( "         P = (1-0.12)*(1-0.12) = 0.88*0.88 = 0.7744 = 0.774 (rounded as requested).    ANSWER\r\n" );
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document.write( "             (My calculations should be clear to you without further explanations !)\r\n" );
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document.write( "(c)  If you randomly select two peanut M&M’s, compute that probability that at least one of them is orange.\r\n" );
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document.write( "         P = 0.23*0.23 + 0.23*(1-0.23)\r\n" );
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document.write( "             This time  YOU  make all necessary calculations and rounding on your own.\r\n" );
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document.write( "             Happy calculations !\r\n" );
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\n" ); document.write( "\n" ); document.write( "Who does not like  M&M’s  ?  ?     (rhetoric question . . . )\r
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