document.write( "Question 1134884: A fraction is such that whose numerator is a 4 less than the denominator. If 1 is subtracted from numerator and 3 is added to the denominator, the fraction becomes 1/5. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #752387 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A fraction is such that whose numerator is a 4 less than the denominator. \n" ); document.write( "d = n+4 \n" ); document.write( " If 1 is subtracted from numerator and 3 is added to the denominator, the fraction becomes 1/5. \n" ); document.write( " \n" ); document.write( "replace d with with n+4 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "5(n-1) = n + 7 \n" ); document.write( "5n - 5 = n + 7 \n" ); document.write( "5n - n = 7 + 5 \n" ); document.write( "4n = 12 \n" ); document.write( "n = 12/4 \n" ); document.write( "n = 3 \n" ); document.write( "then \n" ); document.write( "d = 4 + 3 \n" ); document.write( "d = 7 \n" ); document.write( "Find the original fraction. \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check in the statement \n" ); document.write( "\"If 1 is subtracted from numerator and 3 is added to the denominator, the fraction becomes 1/5.\" \n" ); document.write( "(3-1)/(7+3) = 2/10 = 1/5 \n" ); document.write( " |