document.write( "Question 1134884: A fraction is such that whose numerator is a 4 less than the denominator. If 1 is subtracted from numerator and 3 is added to the denominator, the fraction becomes 1/5. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #752387 by ankor@dixie-net.com(22740)\"\" \"About 
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A fraction is such that whose numerator is a 4 less than the denominator.
\n" ); document.write( "d = n+4
\n" ); document.write( " If 1 is subtracted from numerator and 3 is added to the denominator, the fraction becomes 1/5.
\n" ); document.write( "\"%28%28n-1%29%29%2F%28%28d%2B3%29%29\" = \"1%2F5\"
\n" ); document.write( "replace d with with n+4
\n" ); document.write( "\"%28%28n-1%29%29%2F%28%28n%2B4%2B3%29%29\" = \"1%2F5\"
\n" ); document.write( "\"%28%28n-1%29%29%2F%28%28n%2B7%29%29\" = \"1%2F5\"
\n" ); document.write( "cross multiply
\n" ); document.write( "5(n-1) = n + 7
\n" ); document.write( "5n - 5 = n + 7
\n" ); document.write( "5n - n = 7 + 5
\n" ); document.write( "4n = 12
\n" ); document.write( "n = 12/4
\n" ); document.write( "n = 3
\n" ); document.write( "then
\n" ); document.write( "d = 4 + 3
\n" ); document.write( "d = 7
\n" ); document.write( "Find the original fraction.
\n" ); document.write( "\"3%2F7\"
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check in the statement
\n" ); document.write( "\"If 1 is subtracted from numerator and 3 is added to the denominator, the fraction becomes 1/5.\"
\n" ); document.write( "(3-1)/(7+3) = 2/10 = 1/5
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