document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=103491>Question 103491</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A parsec is approximately <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3.1 ALIGN=MIDDLE  ALT=\"3.1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x10%5E16 ALIGN=MIDDLE  ALT=\"x10%5E16\"   DISABLED_style= \"max-width:90%; height:auto;\" > meters.  How many meters are there in <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8+x+10%5E13 ALIGN=MIDDLE  ALT=\"8+x+10%5E13\"   DISABLED_style= \"max-width:90%; height:auto;\" > parsecs </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75236 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A parsec is approx 3.1x10^16 meters.How many meters are there in 8x10^13 parsecs<BR>\n" );
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document.write( "(8x10^13 p)*(3.1x10^16 m/p) = (8*3.1x10^29) = 24.8x10^29 = 2.48x10^30 meters<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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