document.write( "Question 103473: The length of a rectangle is 1 cm longer than its width. If the diagonal
\n" ); document.write( "of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?
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Algebra.Com's Answer #75233 by checkley75(3666)\"\" \"About 
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LENGTH=W+1
\n" ); document.write( "WIDTH=W
\n" ); document.write( "W^2+(W+1)2=4^2
\n" ); document.write( "W^2+W^2+2W+1=16
\n" ); document.write( "2W^2+2W+1-16=0
\n" ); document.write( "2W^2+2W-15=0 USING THE QUADRATIC EQUATION:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "W=(-2+-SQRT[2^2-4*2*-15])/2*2
\n" ); document.write( "W=(-2+-SQRT[4+120])/4
\n" ); document.write( "W=(-2+-SQRT124)/4
\n" ); document.write( "W=(-2+-11.14)/4
\n" ); document.write( "W=(-2+11.14)/4
\n" ); document.write( "W=9.14/4
\n" ); document.write( "W=2.28 ANSWER.
\n" ); document.write( "W=-2-11.14/4
\n" ); document.write( "W=-13.14/4
\n" ); document.write( "W=-3.28 ANSWER.\r
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