document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1134843>Question 1134843</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose the height in inches of adult males in the united states are normally distributed with a mean of 72 inches and a standard deviation of 2 inches.  Find the percent of men wh are between 70 and 72 inches tall?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #752322 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=752322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mean is 72 inches this corresponds to 50% below 72 inches<BR>\n" );
document.write( ":<BR>\n" );
document.write( "z-score(70) = (70 - 72)/2 = -1<BR>\n" );
document.write( ":<BR>\n" );
document.write( "a z-score of -1 corresponds to 15.87% less that 70<BR>\n" );
document.write( ":<BR>\n" );
document.write( "********************************************************************<BR>\n" );
document.write( "Probability of men between 70 and 72 inches = 50.00 - 15.87 = 34.13%<BR>\n" );
document.write( "********************************************************************<BR>\n" );
document.write( ":  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );