document.write( "Question 103462: Word problems are not my stong suit...please help.\r
\n" ); document.write( "\n" ); document.write( "A plane flies 720 mi against a steady 30-mi/hr headwind and then returns to the same point with the wind. If the entire trip takes 10 h., what is the plane's speed in still air?
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Algebra.Com's Answer #75229 by checkley75(3666)\"\" \"About 
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720/(x-30)+720/(x+30)=10
\n" ); document.write( "[720(x+30)+720(x-30)]/(x-30)(x+30=10
\n" ); document.write( "720x+600+720x-600/(x^2-900)=10
\n" ); document.write( "1440x/(x^2-900)=10 cross multiply
\n" ); document.write( "1440x=10x^2-9000
\n" ); document.write( "10x^2-1440x-9000=0
\n" ); document.write( "10(x^2-144-900)=0
\n" ); document.write( "10(x-150)(x+6)=0
\n" ); document.write( "x-150=0
\n" ); document.write( "x=150 mph for the plane.
\n" ); document.write( "proof
\n" ); document.write( "720/(150-30)+720/(150+30)=10
\n" ); document.write( "720/120+720/180=10
\n" ); document.write( "6+4=10
\n" ); document.write( "10=10\r
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