document.write( "Question 1134804: How do I do this problem?\r
\n" ); document.write( "\n" ); document.write( "Problem: There are two naturally occurring isotopes of Chlorine. 35Cl has a mass of 34.9689amu. 37Cl has a mass of 36.9659amu. Determine the abundance of each isotope.\r
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\n" ); document.write( "\n" ); document.write( "35Cl= %\r
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\n" ); document.write( "\n" ); document.write( "The Atomic Mass of Chlorine is 35.453 \n" ); document.write( "
Algebra.Com's Answer #752283 by ikleyn(52814)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "https://answers.yahoo.com/question/index?qid=20180909234750AAwkHUq\r
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\n" ); document.write( "\n" ); document.write( "and read it there.\r
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\n" ); document.write( "\n" ); document.write( "            What follows, is copied and pasted from that Internet page.\r
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\n" ); document.write( "\n" ); document.write( "            I copied and pasted it for you, but I am not responsible for it . . . \r
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document.write( "According to the periodic table, the average mass of one mole of chlorine is 35.453 grams. \r\n" );
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document.write( "Let x be the fraction of the chlorine that is number 35. 1  -  x is the fraction that is number 37. \r\n" );
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document.write( "34.9689 * x + 36.9659 * (1  -  x) = 34.9689 * x + 36.9659  -  36.9659 * x \r\n" );
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document.write( "34.9689 * x + 36.9659  -  36.9659 * x = 35.453 \r\n" );
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document.write( "1.997 * x = 1.5359 \r\n" );
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document.write( "x = 1.5359 รท 1.997 \r\n" );
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document.write( "The decimal fraction is approximately 0.769. This means 76.9% is 35 Cl and 23.1% is 37 Cl. I hope this is helpful for you.\r\n" );
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