document.write( "Question 1134786: The length of the base of a square pyramid is 12 inches. Given that the surface area of the square pyramid is 336 square inches, find the height of the pyramid. \n" ); document.write( "
Algebra.Com's Answer #752271 by ikleyn(52787)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "            The solution by  @josgarithmetic  is   a b s o l u t e l y   w r o n g   and   t o t a l l y   i r r e l e v a n t.\r
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\n" ); document.write( "\n" ); document.write( "            For your safety simply ignore it.\r
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\n" ); document.write( "\n" ); document.write( "            I came to bring the correct solution - see below.\r
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document.write( "1.  First, the lateral surface area of the given pyramid is  \"336+-+12%5E2\" = 336 - 144 = 192 square inches.\r\n" );
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document.write( "2.  The lateral surface area consists of 4 congruent triangles - so the area of each triangle is  \"192%2F4\" = 48 square inches.\r\n" );
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document.write( "3.  The base of each such a triangle is 12 inches; hence, the slant height of the pyramid is  \"%2848%2F12%29%2A2\" = 8 inches.\r\n" );
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document.write( "4.  Then the height of the pyramid is  \"sqrt%288%5E2-%2812%2F2%29%5E2%29\" = \"sqrt%288%5E2-6%5E2%29\" = \"sqrt%2864+-+36%29\" = \"sqrt%2828%29\" = \"2%2Asqrt%287%29\" units.    ANSWER\r\n" );
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