document.write( "Question 1134791: Find an equation in standard form for the hyperbola that satisfies the given conditions.
\n" ); document.write( "Center at​ (0,0) a=4​, e=4​, horizontal focal axis
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Algebra.Com's Answer #752262 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The standard form of a hyperbola that opens sideways is \r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+h%29%5E2+%2F+a%5E2+-+%28y+-+k%29%5E2+%2F+b%5E2+=+1\"\r
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\n" ); document.write( "\n" ); document.write( "if center at​ (\"0\",\"0\"), means \"h=0\" and \"k=0\" and your equation is\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2F+a%5E2+-+y%5E2+%2F+b%5E2+=+1\"\r
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\n" ); document.write( "\n" ); document.write( "if \"a=4%E2%80%8B\", \r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2F+4%5E2+-+y%5E2+%2F+b%5E2+=+1\"\r
\n" ); document.write( "\n" ); document.write( "if \"e=4%E2%80%8B\", horizontal focal axis\r
\n" ); document.write( "\n" ); document.write( "\"e=c%2Fa\"
\n" ); document.write( "\"4=c%2F4\"
\n" ); document.write( "\"c=16\"\r
\n" ); document.write( "\n" ); document.write( "since \"c=sqrt%28a%5E2%2Bb%5E2%29\"...plug in \"a=4\"​, \"c=16\" and solve for \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"16=sqrt%2816%2Bb%5E2%29\".......square both sides\r
\n" ); document.write( "\n" ); document.write( "\"16%5E2=%28sqrt%2816%2Bb%5E2%29%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"256=16%2Bb%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=256-16\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=240\"\r
\n" ); document.write( "\n" ); document.write( "\"b=4sqrt%2815%29\"\r
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\n" ); document.write( "\n" ); document.write( "and your equation is\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2F+16+-+y%5E2+%2F+240+=+1\"\r
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