document.write( "Question 103465: Help Please!\r
\n" ); document.write( "\n" ); document.write( "Kevin earned $165 interest for 1 year on an investment of $1500. At the same rate, what amount of interest would be earned by an investment of $2500? \r
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Algebra.Com's Answer #75226 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
1500x=165
\n" ); document.write( "x=165/1500
\n" ); document.write( "x=.11 or 11% interest
\n" ); document.write( "2500*.11=$275 intrest on $2500 @ 11%.
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