document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1134744>Question 1134744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Today Matt is 5 times the age of his cousin Kristin. In 4 years time, Kristin will be<BR>\n" );
document.write( "one third of Matt’s age. How old will Matt be when Kristin is 40 years old? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #752217 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=752217\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let m equal the age of matt now.<BR>\n" );
document.write( "let k equal the age of kristin now.\r<BR>\n" );
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document.write( "today matt is 5 times the age of kristin.\r<BR>\n" );
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document.write( "the formula for that is m = 5 * k.\r<BR>\n" );
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document.write( "in 4 years time, kristin will be one third the age of matt.\r<BR>\n" );
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document.write( "the formula for that is k + 4 = 1/3 * (m + 4)\r<BR>\n" );
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document.write( "in the second equation, replace m with 5 * k to get:\r<BR>\n" );
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document.write( "k + 4 = 1/3 * (5 * k + 4)\r<BR>\n" );
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document.write( "now that you have one unknown in one equation, you can solve for k.\r<BR>\n" );
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document.write( "start with k + 4 = 1/3 * (5 * k + 4)\r<BR>\n" );
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document.write( "simplify to get k + 4 = 5/3 * k + 4/3\r<BR>\n" );
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document.write( "subtract 4/3 from both sides of this equation to get k + 4 - 4/3 = 5/3 * k\r<BR>\n" );
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document.write( "subtract k from both sides of this equation to get 4 - 4/3 = 5/3 * k - k\r<BR>\n" );
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document.write( "multiply both sides of this equation by 3 to get 12 - 4 = 5 * k - 3 * k\r<BR>\n" );
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document.write( "combine like terms to get 8 = 2 * k\r<BR>\n" );
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document.write( "divide both sides of this equation by 2 to get 4 = k.\r<BR>\n" );
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document.write( "since k = 4, then m = 5 * k becomes m = 5 * 4 = 20.\r<BR>\n" );
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document.write( "kristin is 4 years old and matt is 20 years old today.\r<BR>\n" );
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document.write( "in 4 years, kristin will be 8 years old and matt will be 24 years old.\r<BR>\n" );
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document.write( "20 / 4 = 5, so matt is 5 * the age of kristin today.\r<BR>\n" );
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document.write( "8 / 24 = 1/3, so kkristin will be 1/3 the age of matt in 4 years.\r<BR>\n" );
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document.write( "kristin will be 40 years old in 40 - 4 = 36 years.\r<BR>\n" );
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document.write( "in 36 years, matt will be 20 + 36 = 56 years old.\r<BR>\n" );
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document.write( "your solution is that matt will be 56 years old when kristin is 40 years old.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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