document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=15048>Question 15048</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What are the length and width of a rectangle if the area is 13.5 square feet and the length of one side is .2 the measure of the perimeter? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7522 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let length of rectangle be L and width be W.<BR>\n" );
document.write( "  area = L*W=13.5..........(1)<BR>\n" );
document.write( "  perimeter = 2*(L+W)<BR>\n" );
document.write( "  length of one side =L = 0.2 times perimeter=0.2*2*(L+W)<BR>\n" );
document.write( "       L=0.4*L+0.4*W<BR>\n" );
document.write( "       0.6*L=0.4*W<BR>\n" );
document.write( "       1.5*L = W....substituting in (1)we get<BR>\n" );
document.write( "      1.5*L*L=13.5<BR>\n" );
document.write( "      L*L= 13.5/1.5 =9<BR>\n" );
document.write( "        L=3<BR>\n" );
document.write( " hence  W = 13.5/3 = 4.5 </SPAN>\n" );
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