document.write( "Question 1134694: A tap fills a tank in 60 mins, another tap fills the same tank in 25 mins, and a third tap fills the same tank in 15 mins. How much time will those take if they run at the same time to fill this tank? \n" ); document.write( "
Algebra.Com's Answer #752191 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "In the clearly presented solution from tutor @ikleyn, the problem is solved by the standard algebraic method -- looking at the fraction of the job each tap does in one minute, and solving an equation using the least common denominator of those fractions.

\n" ); document.write( "Here is an alternative method that many students prefer, since it avoids using fractions in the calculations.

\n" ); document.write( "The individual times for the three taps to fill the tank are 60, 25, and 15 minutes.

\n" ); document.write( "(1) Find the least common MULTIPLE of those times -- 300.

\n" ); document.write( "(2) In 300 minutes...
\n" ); document.write( "(a) the first tap could fill the tank 300/60 = 5 times;
\n" ); document.write( "(b) the second tap could fill the tank 300/25 = 12 times; and
\n" ); document.write( "(c) the third tap could fill the tank 300/15 = 20 times.

\n" ); document.write( "So in 300 minutes, the three taps could fill the tank 5+12+20 = 37 times. That means the time required to fill the one tank is 300/37 minutes.
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