document.write( "Question 103458: I need help please with this one...thank you!!!\r
\n" );
document.write( "\n" );
document.write( "A passenger train can travel 325 mi in the same time a freight train takes to travel 200 mi. If the speed of the passenger train is 25 mi/h faster than the speed of the freight train, find the speed of each. \n" );
document.write( "
Algebra.Com's Answer #75219 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! 325/(x+25)=200/x now cross multiply \n" ); document.write( "325x=200(x+25) \n" ); document.write( "325x=200x+5000 \n" ); document.write( "325x-200x=5000 \n" ); document.write( "125x=5000 \n" ); document.write( "x=5000/125 \n" ); document.write( "x=40 mph is the speed of the freight train. \n" ); document.write( "40=25=65 mp for the passenger train. \n" ); document.write( "proof \n" ); document.write( "325/65=200/40 \n" ); document.write( "5=5 \n" ); document.write( " |