document.write( "Question 103413This question is from textbook Algebra and Trigonometry
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document.write( ": I have the following problem. I will be honest, it is for homework, so the answer is not in the back of the book. I am just trying to understand how to properly solve it.\r
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document.write( "y = (x^2 - 4)/2x^4\r
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document.write( "I tried to simplify this on the website and it gave me y - (x^2 - 4)/2x^4 = 0\r
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document.write( "I am suppose to state what the intercept is and what it is symmetric to (y-axis, x-axis and/or origin)\r
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document.write( "Here is what I did.\r
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document.write( "y = (x^2 - 4)/2x^4
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document.write( "y = (x^2 - 4)/(x^2)(2x^2) - I broke apart the 2x^4
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document.write( "y = -4/2x^2 - I thought the x^2 on the bottom of the fraction cancelled out the top.
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document.write( "After that, I did not know what else to do. I could multiply both sides by 2x^2, but that did not seem to get me anywhere, so I started by making a list of the possible values of x and y.\r
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document.write( "Here is what I came up with.
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document.write( "x = 2, y = -1/2
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document.write( "x = -2, y = -1/2
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document.write( "x = 1, y = -2\r
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document.write( "I plotted these and my answer was the following:
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document.write( "1. I could not find an intercept. I don't see where either can equal 0, unless they both equal 0.
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document.write( "2. They would be symmetric to the y-axis.\r
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document.write( "Am I correct? My main goal is to find out what else to do with the equation. I'm lost.\r
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document.write( "Thanks for your help in advance. \n" );
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Algebra.Com's Answer #75216 by Fombitz(32388) You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "You're on the right track but you lost some terms. \n" ); document.write( "Let's back up. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "I don't think doing the division gives you any more insight. I think it's better to go back the your original form. \n" ); document.write( " \n" ); document.write( "First off, where does this equation equal zero. The most obvious place is when the numerator equals zero. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x=2 and x=-2 are both points where y=0. \n" ); document.write( "To check for symmetry, do as you did before. \n" ); document.write( "Try a number and its negative and see what you get for a result. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "If you look at the equation you are squaring x and squaring the square of x. Working with squares of negatives and positives will give you the same answer so you graph will be symmetric about the y axis. \n" ); document.write( "You can also graph some points and look at the graph. \n" ); document.write( " \n" ); document.write( "As you can see, the graph plummets as x or -x approaches 0 because \n" ); document.write( " \n" ); document.write( "After you pass x=2 in the positive sense and x=-2 in the negative sense, you have a slight increase above zero and then quickly approach zero as x gets larger. There is a maximum value of y=0.0312 at x=+/-2.8 and then quickly head towards zero. Easiest way to see this is to use EXCEL to calculate a bunch of x,y points (use one column for your x values and then the next column use a formula for your y values). Then you can graph that also. \n" ); document.write( " \n" ); document.write( "Additionally from your graph and from looking at the values you see that: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Hope it helps. Good Luck! \n" ); document.write( " |