document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=802602>Question 802602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Good day, <BR>\n" );
document.write( "My question is that I could use some assistance with is (thanks in advance!):\r<BR>\n" );
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document.write( "Given that theta = 17pi/6 use the period of the functions as well as the special angles to find the exact values (does this mean radians?) of the sin, cos and tan of theta.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #752134 by </B><A HREF=/tutors/aboutme.mpl?userid=Math1337><B>Math1337(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Math1337><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=752134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I challenge the previous answer's correctness, which states as follows:\r<BR>\n" );
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document.write( "Given that theta = 17pi/6, find the exact values of the sin, cos and tan of theta.<BR>\n" );
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document.write( "What you need to know is the reference angle of given angle theta=17π/6, and which quadrant it is in.<BR>\n" );
document.write( "17π/6 is like rotating counter-clockwise around the unit circle 16π plus an additional π/6, which places the reference angle of π/6 in quadrant I.<BR>\n" );
document.write( "sin(17π/6)=sin(π/6)=1/2<BR>\n" );
document.write( "cos(17π/6)=cos(π/6)=√3/2<BR>\n" );
document.write( "tan(17π/6)=tan(π/6)=sin/cos=1/√3=√3/3\r<BR>\n" );
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document.write( "The above solution is incorrect.\r<BR>\n" );
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document.write( "Correct Answer:\r<BR>\n" );
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document.write( "If theta = 17π/6, then when finding the quadrant, \r<BR>\n" );
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document.write( "The mistake above is in finding the correct quadrant of the unit circle.\r<BR>\n" );
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document.write( "Rotating 17π/6 is NOT \"like rotating counter-clockwise around the unit circle 16π plus an additional π/6.\"\r<BR>\n" );
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document.write( "It is rotating 2π then an additional 5π/6, or rotating 3π minus π/6, which would place it in quadrant II.\r<BR>\n" );
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document.write( "Thus, \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%28%2817pi%29%2F6%29=sin%282pi%2B5pi%2F6%29=1%2F2 ALIGN=MIDDLE  ALT=\"sin%28%2817pi%29%2F6%29=sin%282pi%2B5pi%2F6%29=1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%28%2817pi%29%2F6%29=cos%283pi-pi%2F6%29=-cos%28pi%2F6%29=-sqrt%283%29%2F2 ALIGN=MIDDLE  ALT=\"cos%28%2817pi%29%2F6%29=cos%283pi-pi%2F6%29=-cos%28pi%2F6%29=-sqrt%283%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%28%2817pi%29%2F6%29=tan%283pi-pi%2F6%29=tan%28-pi%2F6%29=-1%2Fsqrt%283%29=-sqrt%283%29%2F3 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "QED\r<BR>\n" );
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