document.write( "Question 1134668: Determine weight of a block of marble, which contains 130.71 ft.^3 and specific gravity of 2.742.\r
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document.write( "Density = Mass / Volume\r
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document.write( "Unsure how to solve. \n" );
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Algebra.Com's Answer #752127 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Your problem, as it is formulated and presented, has an \"underwater stone\".\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The volume is given in cubic feet, while the specific gravity goes with no measuring unit, at all.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "But I know \"the numbers\", and I know that 2.742 is the marble's specific gravity measured in g/cm^3 or tons/m^3.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Actually, Weight = specific gravity * Volume,\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "but this formula assumes that all the values go with coherent (=consistent) units.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "At this point I will stop my tales.\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "My impression is that you retrieve your problems from a VERY OLD source . . . \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |