document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1134632>Question 1134632</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a man walks a distance at 3 mph and jogs back the same route at 5 mph and the trip takes  one hour  how many miles did he travel </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #752112 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=752112\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is yet another way to solve the problem.<br><BR>\n" );
document.write( "As tutor @ikleyn states in her response, it is always worthwhile to know different ways to solve problems.  In a particular problem, one method might be far easier to use than another.<br><BR>\n" );
document.write( "The distances both ways are the same, and the ratio of the rates is 3:5.  That means the ratio of the times is 5:3.<br><BR>\n" );
document.write( "So the man spent 5/8 of the time at the lower rate and 3/8 of the time at the higher rate.<br><BR>\n" );
document.write( "Since the total time was 1 hour, he spent 5/8 of an hour at 3mph, traveling (5/8)*3 = 15/8 miles; and he spent 3/8 of an hour at 5mph, traveling (3/8)*5) = 15/8 miles.<br><BR>\n" );
document.write( "So the total distance he traveled is 15/8+15/8 = 15/4 miles.   </SPAN>\n" );
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