document.write( "Question 1134637: Suppose Z is a standard normal random variable.\r
\n" ); document.write( "\n" ); document.write( "1. If P(-z < Z < z) = 0.5098, find z.\r
\n" ); document.write( "\n" ); document.write( "2. Find P(-2.11 < Z < -0.37).
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Algebra.Com's Answer #752104 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
1. If P(-z < Z < z) = 0.5098, find z.\r
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\n" ); document.write( "\n" ); document.write( "the area between -z and z is equal to .5098.\r
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\n" ); document.write( "\n" ); document.write( "the z-score in the middle between -z and z is equal to 0.\r
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\n" ); document.write( "\n" ); document.write( "the area to the left of a z-score of 0 is equal to .5.\r
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\n" ); document.write( "\n" ); document.write( "the area between -z and 0 is half the area between 0 and z.\r
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\n" ); document.write( "\n" ); document.write( "because the normal distribution is symmetric, take .5098 and divide it by 2 to get .2549.\r
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\n" ); document.write( "\n" ); document.write( "the area to the left of 0 is equal to .5\r
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\n" ); document.write( "\n" ); document.write( "the between -z and 0 is equal to .2549.\r
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\n" ); document.write( "\n" ); document.write( "subtract .2549 from .5 to get .2451.\r
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\n" ); document.write( "\n" ); document.write( "that's the area to the left of -z.\r
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\n" ); document.write( "\n" ); document.write( "solve for -z to get -z = -.6899907576.\r
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\n" ); document.write( "\n" ); document.write( "that makes z = .699907576.\r
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\n" ); document.write( "\n" ); document.write( "that's your solution.\r
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\n" ); document.write( "\n" ); document.write( "the area between -.6899907576 and .699907576 is equal to .5098001472 which is equal to .5098 when rounded to 4 decimal digits.\r
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\n" ); document.write( "\n" ); document.write( "the solution is confirmed to be good.\r
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\n" ); document.write( "\n" ); document.write( "visually it looks like this.\r
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\n" ); document.write( "\n" ); document.write( "2. Find P(-2.11 < Z < -0.37).\r
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\n" ); document.write( "\n" ); document.write( "the area between -2.11 and -.37 is equal to .3382621848\r
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\n" ); document.write( "\n" ); document.write( "i think that's what you're looking for.\r
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\n" ); document.write( "\n" ); document.write( "if it isn't, let me know what it is that you're looking for here.\r
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\n" ); document.write( "\n" ); document.write( "here's a visual display of what i think you are looking for.\r
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\n" ); document.write( "\n" ); document.write( "you look up the area to the left of a z-score of -2.11 and you look up the area to the left of a z-score of -.37 and you subtract the smaller area from the larger area to get your anser.\r
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\n" ); document.write( "\n" ); document.write( "using my calculator, i got the following:\r
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\n" ); document.write( "\n" ); document.write( "area to the left of a z-score of -2.11 is equal to .0174291159\r
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\n" ); document.write( "\n" ); document.write( "area to the left of a z-score of -.37 is equal to .3556913007\r
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\n" ); document.write( "\n" ); document.write( "after between -2.11 and -.37 is equal to .3556913007 minus .0174291159 which is equal to .3382621848.\r
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\n" ); document.write( "\n" ); document.write( "that's the same as i got before when i asked the calculator for the area between a z-score of -2.11 and -.37 directly.\r
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\n" ); document.write( "\n" ); document.write( "the calculator i use is the TI-84 Plus to solve problems like these.\r
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\n" ); document.write( "\n" ); document.write( "here's a visual display.\r
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\n" ); document.write( "\n" ); document.write( "let meknow if you have any questions or need further clarification on points you don't understand.\r
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