document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1134646>Question 1134646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3 5/6 - 1 1/4 + 1 1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #752092 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=752092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3 5/6 - 1 1/4 + 1 1/2<BR>\n" );
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document.write( "Change to \"improper fractions.\"<BR>\n" );
document.write( "= (23/6) - (5/4) + (3/2)<BR>\n" );
document.write( "You might spot the the LCD (Least Commom Denominator) is 12.<BR>\n" );
document.write( "You might not.<BR>\n" );
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document.write( "The product of the DENs always works.<BR>\n" );
document.write( "6*4*2 = 48<BR>\n" );
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document.write( "(23/6) - (5/4) + (3/2) = (184/48) - 60/48) + (72/48)<BR>\n" );
document.write( "= (184 - 60 + 72)/48<BR>\n" );
document.write( "= 196/48<BR>\n" );
document.write( "Then reducing is easy.<BR>\n" );
document.write( "= 49/12<BR>\n" );
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document.write( "You can use the product of the DEN's, then, if it's asked for, the result is in the LCD.<BR>\n" );
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document.write( "Wasting time and fretting about the LCD accomplishes nothing.<BR>\n" );
document.write( "Using the product ALWAYS works, and reducing is easy.<BR>\n" );
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