document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1134559>Question 1134559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the number of students in a lecture room is inversely proportional to the square root of the number of lectures in a class of 30 students <BR>\n" );
document.write( "there were 25 lectures. what is the evaluation connecting the students and the lectures. find the number of lectures that will be involved when there were 50students </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #752076 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=752076\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> s and l are variables<BR>\n" );
document.write( "s=k/sqrt(l)<BR>\n" );
document.write( "30=k/sqrt(25)=k/5<BR>\n" );
document.write( "k=150\r<BR>\n" );
document.write( "\n" );
document.write( "use k in next part<BR>\n" );
document.write( "50=150/sqrt(l)<BR>\n" );
document.write( "sqrt(l)=3<BR>\n" );
document.write( "l=9 lectures </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );