document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1134635>Question 1134635</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A carpenter and a helper can do a certain job in 18 days. If the carpenter works 1.50 times as fast as the helper, how long would it take each, working alone, to do the job? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #752075 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=752075\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> carpenter and helper do 1/18 of the job in 1 day.<BR>\n" );
document.write( "helper can do it in x days and does 1/x of it in 1 day<BR>\n" );
document.write( "carpenter can do it in x/1.5 days and does 1/x/1.5 or 1.5/x of it in 1 day<BR>\n" );
document.write( "so 1.5/x +1/x=1/18<BR>\n" );
document.write( "multiply by 18x LCD whole thing<BR>\n" );
document.write( "27+18=x=45<BR>\n" );
document.write( "helper needs 45 days<BR>\n" );
document.write( "carpenter needs 30 days<BR>\n" );
document.write( "1/30+1/45=5/90=1/18  This is the right answer, because the helper does 0.02222 of the job per day and the carpenter does 1.5 of it or 0.033333.<BR>\n" );
document.write( "That is 50% faster, and 18 days times the first is 0.40 and 18 days times the second is 0.60 </SPAN>\n" );
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