document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1134598>Question 1134598</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the force acting on a + 10 MuC charge placed 60 cm east of a +6 MuC charge and 40 cm north of a -8 MuC charge (MuC=microcoulomb =10^-6C) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #752070 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=752070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The Coulomb Constant(k) is 8.988 10^9 N * m^2/C^2, where N is newtons and m^^2/C^2 is meters squared per Coulomb squared<BR>\n" );
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document.write( "let +10 MuC charge be q1, +6 MuC charge be q2, and -8 MuC charge be q3<BR>\n" );
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document.write( "let F1 be the force acting on q1, F12 be the force on q1 due to q2, F13 be the force on q1 due to q3, then<BR>\n" );
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document.write( "F1 = F12 + F13<BR>\n" );
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document.write( "the above formula seperates into x and y components<BR>\n" );
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document.write( "F1(x) = F12(x) + F13(x)<BR>\n" );
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document.write( "F1(y) = F12(y) + F13(y)<BR>\n" );
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document.write( "F1(total)  = F1(x) + F1(y)<BR>\n" );
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document.write( "Note r12 = 60 cm is 0.6 m, r13 = 40 cm is 0.4 m<BR>\n" );
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document.write( "Note The point charges q1, q2, q3 are located at the corners of a right triangle<BR>\n" );
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document.write( "Setup a rectangular coordinate system with q1 as the origin<BR>\n" );
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document.write( "Note F12 is a repulsive force acting along the positive portion of the x axis and F13 is an attractive force acting along the negative portion of the y axis<BR>\n" );
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document.write( "F1(x) = (k * q1 * q2)/r12^2 + 0(no x component for F13(x))<BR>\n" );
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document.write( "F1(x) = (8.988 10^9 * 10^-5 * 6 10^-6)/(0.6)^2 = 149.8 10^-2 = 1.5<BR>\n" );
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document.write( "F1(y) = 0 + (8.988 10^9 * 10^-5 * 8 10^-6)/(0.4)^2 = 449.4 10^-2 = 4.5<BR>\n" );
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document.write( "Note F1(y) is negative<BR>\n" );
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document.write( "F1(total) = 1.5 - 4.5 = -3.0 N<BR>\n" );
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