document.write( "Question 1134593: Please help me find the equation of the line that is perpendicular to the line 5x+2y=15 and has an x intercept of 5. \n" ); document.write( "
Algebra.Com's Answer #752006 by Boreal(15235)\"\" \"About 
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rewrite the line given as 2y=-5x+15
\n" ); document.write( "then divide by 2 for y=-(5/2)x+7.5, which is slope intercept form. The slope is -5/2.\r
\n" ); document.write( "\n" ); document.write( "Perpendicular lines have a negative reciprocal slope,meaning their slope product is -1. The slope of the line desired is +2/5
\n" ); document.write( "An x-intercept of (5, 0) is a point
\n" ); document.write( "point slope formula y-y1=m(x-x1) (x1, y1) point
\n" ); document.write( "y=(2/5)(x-5)
\n" ); document.write( "y=(2/5)x-2
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28-5%2F2%29x%2B7.5%2C%282%2F5%29x-2%29\"
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