document.write( "Question 1134593: Please help me find the equation of the line that is perpendicular to the line 5x+2y=15 and has an x intercept of 5. \n" ); document.write( "
Algebra.Com's Answer #752005 by MathLover1(20849)\"\" \"About 
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find the equation of the line that is perpendicular to the line \"5x%2B2y=15\" and has an \"x+\"intercept of \"5\"\r
\n" ); document.write( "\n" ); document.write( " given:\r
\n" ); document.write( "\n" ); document.write( "the line \"5x%2B2y=15\"
\n" ); document.write( "\"x+\"intercept of \"5\"=> it is a point (\"5\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "if the line that is perpendicular to given line, and we know that perpendicular lines have slopes negative reciprocal to each other, we will find slope first\r
\n" ); document.write( "\n" ); document.write( "\"5x%2B2y=15\"...solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"2y=-5x%2B15\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-%285%2F2%29x%2B15%2F2\"-> given line has a slope \"%28-5%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "=>so, perpendicular line will have a slope \"m=%28-1%29%2F%28-5%2F2%29=2%2F5\"\r
\n" ); document.write( "\n" ); document.write( "now use point slope formula to find equation:\r
\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\".....plug in \"m=2%2F5\" and coordinates of the point (\"5\",\"0\") \r
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\n" ); document.write( "\n" ); document.write( "\"y-0=%282%2F5%29%28x-5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%282%2F5%29x-%282%2F5%295\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%282%2F5%29x-%282%2Fcross%285%29%29cross%285%29\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y=%282%2F5%29x-2%29\"\r
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