document.write( "Question 1134558: Given that x = a tan tita
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Algebra.Com's Answer #752001 by ikleyn(52781)\"\" \"About 
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document.write( "Given  x = \"a%2Atan%28theta%29\".\r\n" );
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document.write( "Then  \"1+%2B+x%5E2%2Fa%5E2%29\" = \"1+%2B+%28a%5E2%2Atan%5E2%28theta%29%29%2Fa%5E2\" = \"1+%2B+tan%5E2%28theta%29\" = \"1+%2B+sin%5E2%28theta%29%2Fcos%5E2%28theta%29\" = \"%28cos%5E2%28theta%29+%2B+sin%5E2%28theta%29%29%2Fcos%5E2%28theta%29\" = \"1%2Fcos%5E2%28theta%29\".\r\n" );
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document.write( "Therefore,  \"sqrt%281+%2B+x%5E2%2Fa%5E2%29\" = \"sqrt%281%2Fcos%5E2%28theta%29%29\" = \"1%2Fcos%28theta%29\".\r\n" );
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document.write( "The sign of the resulting expression follows the sign of \"cos%28theta%29\" in its quadrant.\r\n" );
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