document.write( "Question 1134526: An express train travels 348 mi in the same amount of time it takes a freight train to travel 210 mi. The rate of the express train is 23 mph faster than that of the freight train. Find the rate of the freight train.\r
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Algebra.Com's Answer #751942 by ikleyn(52797)\"\" \"About 
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document.write( "Let x be the rate of the freight train, in miles per hour (the value under the problem's question).\r\n" );
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document.write( "Then the time equation is\r\n" );
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document.write( "    \"348%2F%28x%2B23%29\" = \"210%2Fx\".\r\n" );
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document.write( "Solve it for x. Start cross-multiplying\r\n" );
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document.write( "    348x = 210*(x+23),\r\n" );
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document.write( "    348x = 210*x + 210*23\r\n" );
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document.write( "    x = \"%28210%2A23%29%2F%28348-210%29\" = 35.\r\n" );
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document.write( "Answer.  The freight train rate is 35 miles per hour.\r\n" );
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document.write( "If you have questions regarding my solution, send me a message through the \"Thank you\" window/form.\r\n" );
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document.write( "In this case, refer to the problem's ID number, which is 1134526.\r\n" );
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document.write( "Otherwise, I will not know to whom to answer.\r\n" );
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