document.write( "Question 1134506: Find an equation of the circle whose diameter has endpoints (-3,2) and (2,2)
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Algebra.Com's Answer #751909 by mathsolverplus(88)\"\" \"About 
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\"d=sqrt%28%282-%282%29%29%5E2%2B%282-%28-3%29%29%5E2%29\"
\n" ); document.write( "\"d=sqrt%2825%29\"
\n" ); document.write( "\"d=5\"\r
\n" ); document.write( "\n" ); document.write( "If diameter = 5, radius = 2.5 because radius is half of diameter.\r
\n" ); document.write( "\n" ); document.write( "Now, we need to find the center of the circle, which is midpoint between the two given points. \r
\n" ); document.write( "\n" ); document.write( "Midpoint = ((-3+2)/2, (2+2)/2)
\n" ); document.write( " = (-1/2, 2)\r
\n" ); document.write( "\n" ); document.write( "The equation of a circle:
\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\" (h,k) is the center and r = 5/2\r
\n" ); document.write( "\n" ); document.write( "We found center to be (-1/2,2) and radius = 5/2:\r
\n" ); document.write( "\n" ); document.write( "Solution: \"%28x%2B%281%2F2%29%29%5E2%2B%28y-2%29%5E2=25%2F4\" \r
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