document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1134500>Question 1134500</A>: <I><SPAN STYLE=\"word-break: break-all;\"> According to a government study among adults in the 25- to 34-year age group, the mean amount spent per year on reading and entertainment is $1,875. Assume that the distribution of the amounts spent follows the normal distribution with a standard deviation of $640. (Round your z-score computation to 2 decimal places and final answers to 2 decimal places.)\r<BR>\n" );
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document.write( "What percent of the adults spend more than $2,775 per year on reading and entertainment?\r<BR>\n" );
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document.write( "What percent spend between $2,775 and $3,175 per year on reading and entertainment?\r<BR>\n" );
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document.write( "What percent spend less than $1,075 per year on reading and entertainment?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #751903 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=751903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x-mean)/sd<BR>\n" );
document.write( ">2775 is z>(2775-1875)/640 or z> 900/640 or 1.41. This is probability of 0.0793 or 0.08\r<BR>\n" );
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document.write( ">3175 is z>1300/640 or 2.03.  Probability of z between 1.41 and 2.03 is 0.0581 or 0.06\r<BR>\n" );
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document.write( "<1075 is z<(-800/640) or < -1.25 and a probability of 0.1056 or 0.11 </SPAN>\n" );
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