document.write( "Question 1134499: Write the equation of the line that satisfies the given conditions. Express the final equation in standard form. Contains the point (-6,4) and is parallel to the line x-3y=6 \n" ); document.write( "
Algebra.Com's Answer #751896 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "the equation of the line that satisfies the given conditions:\r
\n" ); document.write( "\n" ); document.write( " Contains the point (\"-6\",\"4\") and is \"parallel\" to the line\"+x-3y=6\"\r
\n" ); document.write( "\n" ); document.write( "first, recall that \"parallel\" lines have \"same\" slope\r
\n" ); document.write( "\n" ); document.write( "so, find a slope of the line\"+x-3y=6\"\r
\n" ); document.write( "\n" ); document.write( "\"+x-3y=6\".......solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"+x-6=3y\"\r
\n" ); document.write( "\n" ); document.write( "\"y=x%2F3-6%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%281%2F3%29x-2\"=> slope is \"m=1%2F3\"\r
\n" ); document.write( "\n" ); document.write( "since we have point and slope, use point slope formula to find equation\r
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\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\"........plug in slope \"1%2F3\" and \"x=-6\" and \"y=4\" coordinates of given point\r
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\n" ); document.write( "\n" ); document.write( "\"y-4=%281%2F3%29%28x-%28-6%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y-4=%281%2F3%29%28x%2B6%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y-4=x%2F3%2B6%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"y-4=x%2F3%2B2\"\r
\n" ); document.write( "\n" ); document.write( "\"y-4-x%2F3=2\"\r
\n" ); document.write( "\n" ); document.write( "\"y-x%2F3=2%2B4\"\r
\n" ); document.write( "\n" ); document.write( "\"-x%2F3%2By=62%2B4\"=> the final equation in standard form \r
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