document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1134476>Question 1134476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A journal published a study of​ travelers' familiarity with ecolabels used by hotels. Adult travelers were shown a list of 6 different​ ecolabels, and​ asked, \"How familiar are you with this​ ecolabel?\" Suppose the response is measured on a continuous scale from 10​ (not familiar at​ all) to 50​ (very familiar), and the mean and standard deviation for ecolabel E are 44 and 1.5​, respectively. Assume the distribution of responses is approximately normal. \r<BR>\n" );
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document.write( "a. Find the probability that a response to ecolabel E exceeds 43.<BR>\n" );
document.write( "The probability is </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #751875 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=751875\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1:17): A journal published a study of​ travelers' familiarity with ecolabels used by hotels. Adult travelers were shown a list of 6 different​ ecolabels, and​ asked, \"How familiar are you with this​ ecolabel?\" Suppose the response is measured on a continuous scale from 10​ (not familiar at​ all) to 50​ (very familiar), and the mean and standard deviation for ecolabel E are 44 and 1.5​, respectively. Assume the distribution of responses is approximately normal. <BR>\n" );
document.write( "a. Find the probability that a response to ecolabel E exceeds 43.<BR>\n" );
document.write( "z(43) = (43-44)/1.5 = -1/1.5 = -2/3<BR>\n" );
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document.write( "Ans:: P(x > 43) = P(z > -2/3) = 1-normalcdf(-100,-2/3) = 0.7475<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "The probability is 0.7475 </SPAN>\n" );
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