document.write( "Question 1134468: The length of a rectangular piece of property is one meter more than twice the width. If the perimeter of the property is 302 meters, find the length and width \n" ); document.write( "
Algebra.Com's Answer #751856 by Theo(13342)![]() ![]() You can put this solution on YOUR website! perimeter is equal to 2 times length + 2 times width.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let L = length \n" ); document.write( "let W = width \n" ); document.write( "let P = perimeter\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P = 2L + 2W = 2 * (L + W)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you are given that the length is one meter more than twice the width.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that makes L = 2W + 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in the formula P = 2 * (L + W), replace L with 2W + 1 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P = 2 * (2W + 1 + W)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get P = 2 * (3W + 1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify further to get P = 6W + 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you are given that the perimeter is equal to 302 meters.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that makes P = 302 which makes P = 6W + 2 which becomes 302 = 6W + 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 2 from both sides of that equation to get 300 = 6W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for W to get W = 300 / 6 = 50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since L = 2W + 1, then L = 101.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have L = 101 and W = 50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P = 2 * (L + W) becomes P = 2 * (151) which becomes P = 302.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solution looks good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solution is the length is equal to 101 and the width is equal to 50.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |